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81*3^2x/3^3=1
We move all terms to the left:
81*3^2x/3^3-(1)=0
We multiply all the terms by the denominator
81*3^2x-1*3^3=0
We add all the numbers together, and all the variables
81*3^2x-27=0
Wy multiply elements
243x^2-27=0
a = 243; b = 0; c = -27;
Δ = b2-4ac
Δ = 02-4·243·(-27)
Δ = 26244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{26244}=162$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-162}{2*243}=\frac{-162}{486} =-1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+162}{2*243}=\frac{162}{486} =1/3 $
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